Saben Lee Height In Feet, Age, Parents, And Girlfriend: How Old Tall? 2019

Saben Lee is a professional basketball player and recently, Utah Jazz selected him in the 2020 NBA Draft as a second-round pick. However, on November 22, 2020, he was traded to the Detroit Pistons. His playing position is a point guard and this is his first season in the NFL but he has not made an appearance yet. 

Before being drafted in the 2020 NFL Draft, he used to play college basketball for Vanderbilt Commodores. He played a total of 96 games for his college team and had an outstanding 13.9 points per game. In early 2020, he had managed to secure his spot in the Second-team of All-SEC. 

10 Facts on Saben Lee:

1. The professional basketball player, Saben Lee has an attractive height of approximately 6 feet and 2 inches tall.
2. According to his Wikipedia, we have found out that he weighs around 83 kilograms currently. 
3. Moving on to Saben Lee’s age, he was born on June 23, 1999, and thus, he is currently just 21 years old.
4. As he was born and raised in Phoenix, Arizona, USA, his nationality is clearly known to be American. 
5. Currently, we do not have any details regarding Saben Lee’s parents and it also seems that he has not spoken about his siblings yet.
6. Moreover, he can be found active on Instagram as @_sabenlee and has managed to gain a total of 7.2 thousand followers already. 
7. From his Instagram profile, we have found out that Saben Lee has a girlfriend whose name is Peyton Cutshall. 
8. Speaking about his education, he had completed his high school studies at Corona del Sol High School and he also attended Vanderbilt University. 
9. As per official reports, he has an approximate net worth which is in the range of around $1 million to $5 million.
10. As of now, Saben has been wearing jersey no. 38 for Detroit Pistons.